6k^2+15k+6=0

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Solution for 6k^2+15k+6=0 equation: 



6k^2+15k+6=0

a = 6; b = 15; c = +6;
Δ = b2-4ac
Δ = 152-4·6·6
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*6}=\frac{-24}{12}
=-2
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*6}=\frac{-6}{12}
=-1/2
$

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